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AoSHQ Writers Group
A site for members of the Horde to post their stories seeking beta readers, editing help, brainstorming, and story ideas. Also to share links to potential publishing outlets, writing help sites, and videos posting tips to get published.
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A great many of you remember the game show, “Let’s Make a Deal,” and many of you are probably familiar with “The Monty Hall Problem,” named for the show’s host.
This is a logic problem that seems to have an illogical answer, but I finally figured out a way to understand it.
Let’s say you are a contestant on “Let’s Make a Deal.” Monty tells you that behind one door is a new car, but behind each of the other two doors is a goat. You have to choose one door. We can all agree that your odds are 1 in 3 of choosing the door with the new car. For argument’s sake, let’s say you choose door #3.
Whether or not you chose the door which hides the car, there is a 100% chance that there is a goat behind at least one of the other two doors. Monty then opens one of those doors, revealing a goat. In this case we’ll say it’s door #1. Monty then offers you the opportunity to change your door from door #3 to door #2. Should you do so?
The answer is “Yes.” Your odds will increase from 33% to 67% if you switch.
When I first heard about this, I could not wrap my brain around it. In my mind, there is a 1 in 3 chance I chose the correct door, and since Monty always had a door with a goat behind it to challenge my initial choice, I couldn’t see how my odds would change once Monty revealed a goat. So I actually played it out, and that’s when it all made sense.
If I initially chose the correct door - a 33% chance - I would always lose once I changed doors after being shown the goat.
But if I initially chose one of the two wrong doors - a 67% chance - I would always switch to the correct door after being shown the goat.
Therefore, my odds switch from 33% to 67% of correctly choosing the new car.
So back to our example, if you chose door #3 and the car was actually behind door #3, you would lose after switching. But if you chose door #3 and the car was behind either door #1 or door #2, you would be guaranteed to choose the winning door after the goat was revealed and you switched doors.
Here’s a little of Monty’s dealmaking. Also, open thread.